1S Summer exam June 1996
Calculus, Dr Paul May

1) Determine the following:

a) dy/dx  if  y = x2                 b) dy/dr if y = 3r6 - r + 1

c) dy/dx  if  y = 3cos x          d) dp/dq if p = 5e-q     (7 marks)

2) Differentiate the following functions with respect to x, and simplify the result where possible:

a) y = (x + 1)(x - 1)           b) y = x ln x

c)                    d) y = sin (x2 + 3)    (7 marks)

3) A function which is often used to represent the form of an electronic wavefunction in certain atoms is:

y = r3 e-r

a) This function has 3 stationary points. One is at r = 0, and another at r = infinity. Differentiate this function and thence determine the coordinates (y,r) of the remaining stationary point.     (6 marks)

b) The second differential of this function is:

Determine whether the stationary point you just found is a local maximum or minimum.      (2 Marks)

c) Hence sketch this function between r = 0 and r = infinity.     (3 marks)


Answers

1) [1mark for (a), 2 marks for the rest].

a) dy/dx = 2x          b) dy/dr = 18r5 - 1

c) dy/dx = -3sin x          d) dp/dq = -5e-q

2) [1 mark for (a), 2 marks for the rest].

a) Product Rule: (x + 1).1 + (x-1).1 = 2x

b) Product Rule: x(1/x) + (ln x).1 = 1 + ln x

c) Quotient Rule: =

d) Function of a Function: cos (x2 + 3).2x = 2x cos (x2 + 3)

3) a) [6 marks in total]

Product Rule: -r3e-r + e-r(3r2) = r2e-r(3 - r)

For turning point, r2e-r(3 - r) = 0, so either:
          r2 = 0, so that r = 0,
          e-r = 0, so that r = infinity
or       (3 - r) = 0, so that r = 3

The last answer is the required one. So the turning point is at (3, 1.344).

b) Determine the sign of the second differential, d2y/dr2. Putting in the value of r = 3, we get d2y/dr2 = -0.448, which is -ve, so the t.p. is a local maximum. [2 marks]

c) Sketch: 3 marks