In a free metal ion (this is hypothetical because it does not actually exist!), the five d orbitals are degenerate. When this ion is surrounded by ligands, there is a net stabilisation due to electrostatic attraction between the positive TM ion and the negatively charged ligands, but there also exists an electron- electron repulsion between the outer shell electrons of the metal and the ligands. This repulsion varies in size for each d orbital depending on whether it is pointing directly to a ligand or not. This leads to the degeneracy of the d orbitals, hence the term "Crystal Field Splitting". For more information look at the crystal field splitting diagrams for an octahedral field or a tetrahedral field or a square planar field.
It should be noted that a few assumptions are made in this theory which are not exactly true. Firstly, the TM is assumed to be a positively charged ion, and ligands are negatively charged ions (but the TM can be neutral, cationic or anionic and the ligand can be neutral as well as negatively charged). It follows from this assumption that the electrostatic attraction between the TM and ligands form the ionic bonds (but we know that the bonding is actually coordinate).
An important concept to appreciate is whether the electron chooses high spin or low spin. Basically if the splitting of the d orbitals is large, low spin is preferred (i.e electrons would prefer to pair); but small splitting favours high spin (electrons would rather occupy orbitals singly). The size of splitting is affected by several factors:
For fuller explanations, look at:
Splitting Diagram for Octahedral Complex
Splitting Diagram for Tetrahedral Complex
Splitting Diagram for Square Planar Complex
Before we can assign electrons to orbitals in order to predict the magnetic behaviour of a compound , we must first decide whether the electron chooses high spin or low spin. High spin favours the maximum number of unpaired electrons (upe`s). Low Spin favours the minimun number of upe`s (i.e prefers pairing). For example when the fourth electron is loaded onto an octahedral structure, it may be paired up in the lower level ,t2g, illustrating low spin, or it can occupy singly in the higher level, eg, (high spin).
This choice is affected by two factors:
If the size of splitting is larger than pairing energy, low spin is preferred, if vice versa, then high spin is preferred. Firstly let us consider the pairing energy. The pairing energy decreases as the d orbital gets larger. Therefore going from the First TM Series to the Second, pairing energy decreases which implies that low spin is favoured.
The size of splitting is more complicated because it is affected by three other factors:
Compound | Size of Splitting | e- configuration | Spin | Number of upe`s |
---|---|---|---|---|
[Fe(NH 3)6] 2+ | Splitting < Pairing energy | d6 | High Spin | 4 upe`s |
[Co(NH3)6]3+ | Splitting > Pairing energy | d6 | Low Spin | 0 upe`s |
Click here to see illustrations of high spin vs low spin .
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Page by Josephine Yuen: jy6984@bristol.ac.uk
Last updated April 1997© 1997